The distance from Seymour, Indiana to Fargo, North Dakota

The exact distance between Seymour, Indiana and Fargo, North Dakota is 775 miles (1248 kilometers) by a straight line.

The distance from Seymour, Indiana 
to Fargo, North Dakota
The distance from Seymour, Indiana to Fargo, North Dakota by highways is about 938 miles and it is subject to a slight change depending on the chosen route. Travel time from Seymour, Indiana to Fargo, North Dakota by car is about 15.6 hours and it also may vary depending on traffic. Upon planning a journey from Seymour to Fargo please keep in mind that travel times may become much longer in case of traffic jams or bad weather. You can also use a public transport system to move between Seymour, Indiana and Fargo, North Dakota.



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Where next? Distances to other cities from Fargo, North Dakota: