The distance from Seymour, Connecticut to Fargo, North Dakota

The exact distance between Seymour, Connecticut and Fargo, North Dakota is 1230 miles (1980 kilometers) by a straight line.

The distance from Seymour, Connecticut 
to Fargo, North Dakota
The distance from Seymour, Connecticut to Fargo, North Dakota by highways is about 1513 miles and it is subject to a slight change depending on the chosen route. Travel time from Seymour, Connecticut to Fargo, North Dakota by car is about 25.2 hours and it also may vary depending on traffic. Upon planning a journey from Seymour to Fargo please do not forget that travel times may differ from the above in case of traffic jams or bad weather. You can also use a public transport system to move between Seymour, Connecticut and Fargo, North Dakota.



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